View Full Version : 8 and 16 ohm load in parallal?
ccoker
12-21-2005, 01:47 PM
I want to try a 3 speaker combo, have 3 8om speakers
two 8s in series for 16
and an 8ohm
if I had these in parallel, it would be what? 12ohms?
or I could wire the 8s in parallel for 4
wire that in series with the 8 would yield what, 12 ohms?
that seems obvious
it's the 16 with the 8 in parallel that has me perplexed
ideally a single 16 wire in parallel with the two 8s in series would have a net load of 8 ohms
hasserl
12-21-2005, 02:23 PM
Randall Aiken has some good info on adding components in series and parrallel on his site: http://aikenamps.com/ Look in the Tech Info / Introductory
Hope that helps,
Hasse
bob-i
12-21-2005, 02:29 PM
I want to try a 3 speaker combo, have 3 8om speakers
two 8s in series for 16
and an 8ohm
if I had these in parallel, it would be what? 12ohms?
Let's see...
1/16+1/8=
1/16+2/8=3/16
16/3=5.3333
Your resulting load will be 5.3 ohms. You could use a 4 ohms tap for this.
or I could wire the 8s in parallel for 4
No... 1/8+1/8+1/8=3/8
8/3=2.666... your load would be 2.666. Not a good idea unless you have a 2 ohm output like a Super Reverb or Tweed Bassman.
wire that in series with the 8 would yield what, 12 ohms?
that seems obvious
No. 8+8+8=24 so that would be 24 ohms. Again not a great idea although with a 16 ohm tap that wouldn't be terrible.
it's the 16 with the 8 in parallel that has me perplexed
Yes, that's not easy to comprehend. The forumla is 1/R1+1/R2+1/R3....=1/Rt
So add up 1/16+1/8 then invert the answer like I did above.
ideally a single 16 wire in parallel with the two 8s in series would have a net load of 8 ohms
It would seem that way, only with you have one speaker of higher impedance than another the result is that the lower impedance speakers receives more of the power. It can make the sound imbalanced and potentially overload the lower impedance speakers.
I hope this helps.
Bob
baald
12-21-2005, 02:35 PM
__/-8-\_8_...=...12 ohms
..\-8-/
___/-8----8-\__..=..5.3 ohms
...\----8---/
make sense?
ccoker
12-21-2005, 02:45 PM
I looked all through there, couldn't find it
Slick51
12-21-2005, 03:06 PM
I looked all through there, couldn't find it
Look again...
Adding Components in Series and Parallel
use the resistor formulae.
Slick51
ccoker
12-21-2005, 04:45 PM
"or I could wire the 8s in parallel for 4 "
I meant wire two of the 8s in parallel for a 4 ohm load
and then wire in the other 8ohm speaker in series with the above for a comined 12 ohnm load
bob-i
12-21-2005, 05:02 PM
"or I could wire the 8s in parallel for 4 "
I meant wire two of the 8s in parallel for a 4 ohm load
and then wire in the other 8ohm speaker in series with the above for a comined 12 ohnm load
Yes, see the diagram that Baald posted, that should help you out.
Personally I'd go with the 5.3ohm load solution I described above, and baald drew up in a nice diagram.
___/-8----8-\__..=..5.3 ohms
...\----8---/
StompBoxBlues
12-22-2005, 07:01 AM
Yes, see the diagram that Baald posted, that should help you out.
Personally I'd go with the 5.3ohm load solution I described above, and baald drew up in a nice diagram.
___/-8----8-\__..=..5.3 ohms
...\----8---/
I didn't see anyone mention it yet, but you MUST also consider the watts the speakers can handle.
In the 5.3 ohm conficuration, The 16 side (the two 8's) together will draw a current that is half what the lone 8 ohm speaker draws!! That means whatever wattage the speakers are rated for, I think the lone 8 ohm will have to handle 2/3's of the amps output watts, while the other side only 1/3.
ccoker
12-22-2005, 09:52 AM
thanks guys..
I have decided to not persue this any further
got my existing cab (2x12) dialed in and it sounds perfect
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