tjs
06-29-2007, 09:43 AM
I'm thinking of building a highly switchable tone stack for the purpose of experimenting with different component values without having to swap parts in and out. I was wondering what the pros and cons are of using a switch for this purpose verses a potentiometer.
For instance, I would like to be able to select slope resistor values of roughly 56k, 100k, and 150k (33k would be nice too, but I can't think of an easy way to add that as an option). The two simplest ways I can think of doing this are as follows:
1) Wire 100k and 150k resistors in parallel and use an on/off/on switch to shunt either or none of them. 100k//150k would give me 60k.
2) Wire a 56k resistor in series with a 100k linear pot. With the pot all the way down I have 56k, at 12:00 I have 106k, and all the way up I have 156k.
The first method would take up less space and the second would give me gradual rather than stepped control of the slope resistance. Would one be preferable to the other in terms of less added noise and signal degradation?
For instance, I would like to be able to select slope resistor values of roughly 56k, 100k, and 150k (33k would be nice too, but I can't think of an easy way to add that as an option). The two simplest ways I can think of doing this are as follows:
1) Wire 100k and 150k resistors in parallel and use an on/off/on switch to shunt either or none of them. 100k//150k would give me 60k.
2) Wire a 56k resistor in series with a 100k linear pot. With the pot all the way down I have 56k, at 12:00 I have 106k, and all the way up I have 156k.
The first method would take up less space and the second would give me gradual rather than stepped control of the slope resistance. Would one be preferable to the other in terms of less added noise and signal degradation?