View Full Version : How to measure current draw on a cathode biased amp?
burner
01-20-2008, 03:59 PM
I have a 5E3 and I'm wondering how I measure the tubes current draw for biasing since I presume there is no 1 ohm resistor to ground.
This is the first cathode biased amplifier I've owned.
Do I measue the voltage across the cathode resistor and divide in half?
thanks
hasserl
01-20-2008, 06:25 PM
1. Measure the voltage drop across the resistor and divide by the value of the resistor. The result is the cathode current of both tubes (not the same as the plate current, but we can work with it).
2. Measure the voltage between the plate and the cathode.
3. Multiply the cathode current by the Plate to Cathode voltage. The result is the total watts for both tubes.
4. Divide by 2 to get the total watts per tube.
burner
01-20-2008, 09:30 PM
1. Measure the voltage drop across the resistor and divide by the value of the resistor. The result is the cathode current of both tubes (not the same as the plate current, but we can work with it).
2. Measure the voltage between the plate and the cathode.
3. Multiply the cathode current by the Plate to Cathode voltage. The result is the total watts for both tubes.
4. Divide by 2 to get the total watts per tube.
Great!
Question though:
Step 2:
I put one lead on the plate pin and one on the cathode pin?
Also to build an adjustable bias, all I need to do is substitue a pot for the Cathode resistor...correct?
Wait...I don't want the total WATTS do I?
I just want the total current in milliamps.
So I would only do step one?
Blue Strat
01-20-2008, 09:46 PM
In reality, you DO want to know idle power (watts) per tube to be sure that you're not running above 12 watts (the maximum rating, which is often violated in 5E3s, for 6V6s). Idle current alone doesn't tell you very much.
No, you cannot install a pot where the cathode resistor is because of the power requirement for that component (10 watts or so). There is a way to do what you want. I'll see if I can find a schematic.
burner
01-20-2008, 10:48 PM
In reality, you DO want to know idle power (watts) per tube to be sure that you're not running above 12 watts (the maximum rating, which is often violated in 5E3s, for 6V6s). Idle current alone doesn't tell you very much.
No, you cannot install a pot where the cathode resistor is because of the power requirement for that component (10 watts or so). There is a way to do what you want. I'll see if I can find a schematic.
Thanks
Yes please do because I'd be interested in adding an adjustable bias.
BTW, I am running 6L6s in this circuit with a 25watt OT
So, that would change the wattage requirements.
I should be able to use 6V6 or 6L6 in the same circuit with very little adjustment
Blue Strat
01-21-2008, 06:05 AM
Be sure that the power transformer is able to supply double the heater current for 6L6s. Standard 5E3 power transformers are unable to do this safely.
Swarty
01-21-2008, 10:50 AM
Thanks
Yes please do because I'd be interested in adding an adjustable bias.
BTW, I am running 6L6s in this circuit with a 25watt OT
So, that would change the wattage requirements.
I should be able to use 6V6 or 6L6 in the same circuit with very little adjustment
Actually EL34/6V6 are very close (typically swapable)(EL34s require much more heater current than 6L6s). 6L6s will require a larger value resistor.
My suggestion is a rotary switch with various cathode resistor values.
burner
01-24-2008, 08:37 PM
Yes it has a 25watt Hammond OT and will run with either 6V6 or 6L6
(Li'l Dawg D'luxe)
I guess I should have specified but I was mainly interested in knowing how to measure how many milliamps the tubes are drawing so that I can alter it to suit if need be.
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