I did a thread search but couldn't find anything that was inline with the question I had, and so I'm sorry for starting yet another impedance question. The situation: I have a Mig100 with 4,4,8Ω outputs and 2 cabs. 1 is 16Ω and another is 8Ω. I also have a Z-matcher. Now I know that if the other cab was 16Ω I could effectively run out of the 8 with a Y splitter and be fine (I have a very basic understanding of matching at least), but since the other cab is 8Ω, I know that's not an option. I also know under most circumstances, I would just have to go with 1 cab, but I didn't know if having a Z matcher would also be able to correct that issue. Thank you in advance for your time and responses.