3 outputs, 2 cabs, 1 Z matcher (impedance)

Discussion in 'Amps/Cabs Tech Corner: Amplifier, Cab & Speakers' started by seisxseisxseis, Feb 23, 2012.

  1. seisxseisxseis

    seisxseisxseis Member

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    I did a thread search but couldn't find anything that was inline with the question I had, and so I'm sorry for starting yet another impedance question.

    The situation: I have a Mig100 with 4,4,8Ω outputs and 2 cabs. 1 is 16Ω and another is 8Ω. I also have a Z-matcher.

    Now I know that if the other cab was 16Ω I could effectively run out of the 8 with a Y splitter and be fine (I have a very basic understanding of matching at least), but since the other cab is 8Ω, I know that's not an option. I also know under most circumstances, I would just have to go with 1 cab, but I didn't know if having a Z matcher would also be able to correct that issue.

    Thank you in advance for your time and responses.
     
  2. oldhousescott

    oldhousescott Silver Supporting Member

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    Hook the 16 to the 8, and the 8 to the 4. You don't need the Z-matcher at this time.
     
  3. seisxseisxseis

    seisxseisxseis Member

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    That's what I thought since (I think I'm right about this...) 16 + 8 = 24/2 = 12 and 8+4 = 12, but I didn't know how exactly that translated across the outputs on the back of the head.

    Thank you for the reply!
     

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