princeton input channels ?

Discussion in 'Amps and Cabs' started by neastguy, Apr 4, 2020.

  1. neastguy

    neastguy Member

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    so I have a princeton clone channel one is louder than channel two.. is it supposed to be like that... ?
     
  2. RicardoUK

    RicardoUK Member

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    Input two is less sensitive (i.e. quieter) and is meant for humbuckers
     
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  3. MkIIC+

    MkIIC+ Silver Supporting Member Supporting Member

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    It’s probably the low input and 6 dBs lower. Since it’s a clone, you may be able to look up a Princeton user manual online to see what it says.

    Personally, I’ve always used the high input on Fender amps regardless of pickups. You’ll get better breakup from the high input when driving the amp. The low input would be more suitable if you are looking to avoid breakup.

    You can also use a boost pedal for more breakup if that’s what you are looking for sound wise.
     
  4. Dan40

    Dan40 Supporting Member

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    As the fellas mentioned above, a Princeton is a single channel amp with a hi an low sensitivity input. Input two will naturally be a bit quieter to allow for the use of higher output pickups.
     
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  5. Bluesful

    Bluesful Supporting Member

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    Is it actually 6dB?
     
  6. MkIIC+

    MkIIC+ Silver Supporting Member Supporting Member

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    I couldn’t say for sure on a clone but it is on a ‘65 Princeton Reissue.

    A . INPUT 1—Full sensitivity input for most guitars.
    B . INPUT 2—Lower sensitivity input (-6dB) to provide high-
    output guitars with cleaner response.
    NOTE: Both inputs become equal in sensitivity when used simultaneously.
     
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  7. HotBluePlates

    HotBluePlates Member

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    Yes, it is. But only if nothing is plugged into Input #1.

    The signal provided to the #2 input has a voltage divider (made of two 68kΩ resistors) which reduces the signal by half, then delivers it to the input stage grid.

    For Voltage, the decibel formula is 20 log (Volts / Volts Reference)

    - Halving the voltage is 0.5 relative to the reference voltage.
    - 20 log (0.5) = 20 * -0.301 = -6.02 dB (we always just say -6dB)​

    For Power, the formula is 10 log (Power / Power Reference). So "half power" is -3dB, but "half voltage" is -6dB.

    - It the dB figures actually work out to say the same thing, because if you apply half-voltage to a fixed resistance, you get half-current. Half-Current * Half-Voltage = Quarter-Power, which is also -6dB. ;)
     
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  8. neastguy

    neastguy Member

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    so second channel is for humbuckers.. seems like the first channel is fine for both
     
  9. Dan40

    Dan40 Supporting Member

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    You have to remember that back when Leo Fender designed these amps, overdrive from humbucking pickups was frowned upon. He wanted the amp to stay clean with whatever guitar the musician chose to use. Nowadays we love the sound of humbuckers through the hotter input!
     
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  10. Bluesful

    Bluesful Supporting Member

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    I think both and fine for both if you know what I mean.

    But that's just me.
     

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