He asked if one could wire four, 8 ohm speakers in such a way that the transformer sees a 4 ohm load. The answer is no. Series/parallel wiring with four, 8 ohm speakers will yield an 8 ohm load.

Jim is correct, unless there is a way I am unaware of. Boy, two wrong answers right off the bat and one from an amp company???? + Series - Parrallel 8+8+8+8 = 16+16 = 32 Ohms Eq: 8+8+8+8=32 8-8-8-8 = 4-4 = 2 Ohms Eq: 1/(1/8+1/8+1/8+1/8)=2 8+8-8+8 = 16-16 = 8 Ohms Eq: 1/(1/(8+8)+1/(8+8))=8 8=8+8=8 = 4+4 = 8 Ohms Eq: (1/(1/8+1/8))+(1/(1/8+1/8))=8